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A quadratic of the form -2x^2 + Bx +C  has roots of 3+ (sqrt 5) and 3- (sqrt 5).The graph of  Y= -2x^2 + Bx +C is a parabola. Find the vertex of this parabola.

 Jul 24, 2020
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This is given      -2 (x-3-sqrt5)(x-3+sqrt5)      multiply it out and reduce by collecting like terms

             and then you will see what  A  and  B    and C    are

   the 'x' of the vertex  is then   - B / 2A

       use this value of 'x' in the equation to compute the 'y' value of the vertex.....

 Jul 24, 2020

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