A quadratic of the form -2x^2 + Bx +C has roots of 3+ (sqrt 5) and 3- (sqrt 5).The graph of Y= -2x^2 + Bx +C is a parabola. Find the vertex of this parabola.
+37146 This is given -2 (x-3-sqrt5)(x-3+sqrt5) multiply it out and reduce by collecting like terms
and then you will see what A and B and C are
the 'x' of the vertex is then - B / 2A
use this value of 'x' in the equation to compute the 'y' value of the vertex.....
