0.0015926535897932+(22/7-pi) = 0.0028571428571428187 = 1/350
Area 6 x 8 + 3 x8 + 3x8 + 3x8 + 1/2 (3+6) x 2.6 x 2 mi2
Volume 1/2 (3+6) x 2.6 x8 mi3 You are left to do the calculations.....
When the ball hits the ground, h will = 0
0 = -16t^2 + 28t + 144 Use quadratic formula to find t .... throw out negative t values
a = -16 b = 28 c = 144
\(t = {-28 \pm \sqrt{28^2-4(-16)(144)} \over 2(-16)}\)
Which of the choices have roots (i.e. are equal to zero) at x = -1 2 and 3 ?
that makes it pretty easy......
Slope = -9/-3 = 3
y = 3x + b sub in one of the given points to calc b
3 = 3(4) + b b = -9
Angle A and B are equal = 75 degrees
6 sin 75 = height = ~ 5.8 6 cos 75 = 1/2 of the base base = 3.1
area = 1/2 base * height = 1/2 3.1 * 5.8 = 9 units2
A petagram is 1015 grams
2 x 10-16 gm / 1015 gm/ petagram = 2 x 10-31 petagram
Slope of given line = +2 perpindicular = - 1/2
point slope form (y-g)= -1/2 (x-f)
Guess I did too many steps in my head and lost ya
15 = k 4^r = k * (2^2)^r = k * 2^2r
3 = k 2^r and 15 = k 2^2r
Multiply first equation by 5
5 k 2^r = k 2^2r divide out k
5 * 2^r = 2^2r
log 5 + r log 2 = 2r log 2
log 5 = r (2log2 - log2)
log5 / log 2 = r = 2.321928095 (and k = 3/5)
