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What is the right equation?

 

 Aug 8, 2020
 #1
avatar+169 
+2

Should be a, if i am not mistaken

f(x)=(x-2)^2(x+1)(x-3)

 Aug 8, 2020
 #2
avatar+26626 
+1

Which of the choices have roots (i.e.  are equal to zero) at x = -1   2   and 3   ?

   that makes it pretty easy......

 Aug 8, 2020
 #3
avatar+169 
+1

ahh yes

i did it a different way

this is easier though

Inspirational  Aug 8, 2020
 #4
avatar+8 
0

It's f(x)=(x-2)^2(x+1)(x-3) because it passes y=0 at x=-1,2,3 so the solution of f(x)=0 is -1,2,3.

 Aug 8, 2020

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