First....realize this is a right triangle
Pythagorean theorem
(sqrt5)^2 + (sqrt8)^2 = sqrt13 ^2
area = 1/2 b * h = 1/2 (sqrt5 * sqrt8 ) = sqrt 10 units2
x+y = 124
5x + 10y = 840 x = # 5 dollar bills y = #10 dollar bills
solve for x and y
sin = -12/13
sec = 1/cos if sec <0 then cos < 0
sin2 + cos2 = 1 yields cos = - 5/13
Tan = sin / cos
csc = 1/sin
sec = 1/cos
cot = cos/sin plug in the values of sin and cos to compute these trig values....
1/3 of the distance = 700 km remaining distance = 1400 km
distance / rate = time
700 km / 760 km/h + 1400 km / 800 km/ hr = ......... hr
Q1 T = 2pi sqrt (L/g)
so gravity is inversely proprtional to T period
L/(T/2pi)2 = g so g is in direct proprtional to L
Q2 net g will be Earth - moon g which will affect T (the period) Moon g will be very small....
4z = 8 so z = 2
3x - 2(2) = 11
so x = 5
z = 2 x = 5 substitute into first equation t calculate 'y'
The shaded area includes everything ABOVE the line ...but NOT the line
equation of the line is y = 1/3x -3
y > 1/3x -3
8 minutes / (5x400)m = .004 min / meter
.004 min/meter * (9 * 200 meters) = 7.2 mins
Here is the completed Venn..... any questions?
*** edit *** that 44 should be a ' 3'
A rate = 100 l / 5 min = 20 l/min
B rate = 100/4 = 25 l/min combined = 45 liters per minute
9000 l / 45 l/ min = 200 min