x^2+16x+y^2-4y+16=0 put in standard form (x-h)^2 + (y-k)^2 = r ^2
by completing the squre for x any
(x+8)^2 + ( y-2)^2 = -16 +64 + 4 r^2 = 52
x = -12 Use that to calc GE
.08(14) = 1.12
.07 (x) = 1.12
x = final amount = 16 final amount - origianl amount = 2 ml of water to add
Numbers are x x+2 and x+4
x + x+2 + 8 = 3 (x+4) - 11 solve for 'x' then the third number is x+4
21 coins
n
p = 4n
d = n+1
q = n-1
n + 4n + n+1 + n-1 = 21
7n = =21
n = 3
then p = 12 d = 4 q = 2
x = $1 bills value = (1)(x) = x
14-x = $ 5 bills value = 5(14-x) summed, they equal $ 50
x + 5 (14-x) =50 solve for x (the number of $1 bills) then $5's = 14-x
t
f = 3t
t = 2s-5 s = (t+5)/2 all three sides sum to 52
t + 3t + (t+5)/2 = 52 solve for t then f = 3t and s = (t+5)/2
If you draw a line through the two given lines, you will find the second line is parallel the graphed line
so There is no solution to the system of equations
Let's just say that thee are 100 people in the room
75 are men
40 have blond hair
100 - 40 = 60
75 - 60 = 15 men would be the least number with blond hair
3 (x^2 + kx + 24)
3 ( x+1)(x+24)
3 (x^2 + 25x + 24 )
(3 x^2 + 75x+72)
(3x+3)(x+24) I think the answer would be n=75 (?)
