Find the area of the triangle with side lengths sqrt(5), sqrt(8), and sqrt(13).
First....realize this is a right triangle
Pythagorean theorem
(sqrt5)^2 + (sqrt8)^2 = sqrt13 ^2
area = 1/2 b * h = 1/2 (sqrt5 * sqrt8 ) = sqrt 10 units2
+37159 
