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Find the area of the triangle with side lengths sqrt(5), sqrt(8), and sqrt(13).

 Sep 16, 2020
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First....realize this is a right triangle

   Pythagorean theorem

       (sqrt5)^2 + (sqrt8)^2 = sqrt13 ^2  

area = 1/2 b * h    = 1/2 (sqrt5 * sqrt8 ) = sqrt 10  units2

 Sep 16, 2020

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