Zeroes at -4 and 2 looks like this
y = a ( x+4)(x-2)
y = a ( x^2 + 2x-8) sub in the point given to calculate a
- 18 = a (1 -2 -8)
a = 2
y = 2 x^2 + 4x -16
11 ft must be one side of the prism there are four sides added = 11 + 11 + 5 + 5 = 32 ft
total side area = 15 x 32 = 480 ft2
The little side flaps are then 5 x 11 * 2 = 110 ft 2
total area = 480 + 110 = 590 ft2
4 ft * 12 in/ ft = 48 inches
x = 35o from the diagram
x + y + y = 180
35 + 2y = 180 solve for 'y'
6 ft 4 in = 76 inches
Tan 40 = opp/adj
Tan 40o = 76/ adj solve for adj which is the shadow length
Missing Sloan's speeds.....
Calculate the area of the WHOLE big rectangle 12 x 13 m2
minus the three 'cutouts'
3 x 3 + 2 * 3*3.5 m2
Very similar....see if you can apply the method to this problem....
https://web2.0calc.com/questions/matthew-has-a-jar-of-368-nickels-and-dimes-he-has#r1
d = # dimes value = 10d
n = nickels = 368 - d value = 5 (368-d) summed = 2840
10d + 5 (388-d) = 2840
solve for 'd' ...the # of dimes then # nickels = 368 - d
w + w + L + L = 8w
2L = 6w
L = 3w
w * 3w = 243
3w^2 = 243
w = 9 in
