Create the equation of a quadratic function in standard form, that has zero’s of {─ 4 and 2} and passes through the point (-1, -18)
If a quadratic has roots {-4, 2}, then f(-4)=0, f(2)=0, which means
f(x)=ax^2+bx+c
f(-4)=x*(-4)^2+b*(-4)+c=0
f(2) = x*(2)^2+b*(2)+c=0
-18=x*(-1)^2-b+c
solve the system of three, unkowns, then plug the values of a, b, c into ax^2+bx+c
+36915 Zeroes at -4 and 2 looks like this
y = a ( x+4)(x-2)
y = a ( x^2 + 2x-8) sub in the point given to calculate a
- 18 = a (1 -2 -8)
a = 2
y = 2 x^2 + 4x -16
