The perimeter of a particular rectangle is eight times its width. If the area of the rectangle is $243\text{ in}^2$, what is the width of the rectangle, in inches?
wait is it 9?
I just calculated it and thats what i got
w + w + L + L = 8w
2L = 6w
L = 3w
w * 3w = 243
3w^2 = 243
w = 9 in
thx I just got it XD
