+0  
 
0
58
4
avatar

The perimeter of a particular rectangle is eight times its width. If the area of the rectangle is $243\text{ in}^2$, what is the width of the rectangle, in inches?

 Mar 4, 2021
 #1
avatar
0

wait is it 9?

 Mar 4, 2021
 #2
avatar
0

I just calculated it and thats what i got

 Mar 4, 2021
 #3
avatar+30523 
+2

w + w    + L + L =  8w

2L = 6w

L = 3w

 

w * 3w = 243

3w^2 = 243

w = 9  in           

 Mar 4, 2021
 #4
avatar
0

thx I just got it XD

 Mar 4, 2021

10 Online Users

avatar