Is there a baseline chirps/minute or temperature from which he (only males chirp) increases 1 chirp/.25 degree f ?
Slope = 1 c/0.25 degree = 4
40 = 4x -160
f(x) = 4x -160 ???????????? Where x = temp and f(x) = chirps
Looked up Dolbear's Law:
Tf = 50 + ( n60-40)/4 n60 = chirps per minute so 40 must be the baseline
= 50 + n60/4 -10
= 40 +n60/4
Tf = n60/4 + 40 there, now I'm happy.....