According to Dolbear’s law, you can predict the temperature TT (in degrees Fahrenheit) by counting the number xx of chirps made by a snowy tree cricket in 1 minute. For each rise in temperature of 0.25°F, the cricket makes an additional chirp each minute.
a. A cricket chirps 40 times in 1 minute when the temperature is 50°F. Write an equation in slope-intercept form that represents the temperature in terms of the number of chirps in 1 minute.
Is there a baseline chirps/minute or temperature from which he (only males chirp) increases 1 chirp/.25 degree f ?
Slope = 1 c/0.25 degree = 4
40 = 4x -160
f(x) = 4x -160 ???????????? Where x = temp and f(x) = chirps
Looked up Dolbear's Law:
Tf = 50 + ( n60-40)/4 n60 = chirps per minute so 40 must be the baseline
= 50 + n60/4 -10
= 40 +n60/4
Tf = n60/4 + 40 there, now I'm happy.....