+4622 You can break the original value into \(\sqrt[3]{16}\sqrt[3]{x^5y^{13}}.\) We know that \(\sqrt[3]{16}=2\sqrt[3]{2}\), because of the power, \(2^4.\) Thus, the answer is \(\boxed{2\sqrt[3]{2}\sqrt[3]{x^5y^{13}}}\).
+37146 ....further y^13 = y^3 y^3 y^3 y^3 y so you can take all of those y^3 's out
and x^5 = x^3 x^2 so you can take the x^3 out
2 x y^4 \(\sqrt[3]{2x^2 y}\)
