The area to the LEFT of the center of the circle is given by
1km x . 8km = .8km^2
Subtract the 1/2 circle area : - 1/2 pi (.8km/2)^2 = - .2513 km^2
.8 - .2513 = .5486 km^2
Total rectangular area is (1+1.4)km x (.8 km) = 1.92 km^2
.5486 km^2/ 1.92 km^2 = .286 = 28.6 % chance of landing in that little area...
Me thinks you are talking about WINDCHILL.....which is not the actual temp.
The record low for MN was -60 in Feb 1996.
Factors of 700 : 1,2,4,5,7,10,14,20,25,28,35,50,70,100,140,175,350,700
Maybe the ones in red? Like answer is 8??
Yah....back in CO......Dallas last week.....Minnesota the week before that (when it was -30 cool).... took the dogs for a few runs in the -20 range.....we didn't go very far !
6 degrees here today...woooohoooo! Snow is great!!
Area of top triangle = 1/2 b h = 1/2 5 * 7.5 = 18.75 sq in there are two of these triangles = 37.5 sq in
Area of lower 1/2 7.5 * 14 = 52.5 = 105
Total area = 37.5 + 105 = 142.5 in^2
These would be MUCH easier to get an answer if you would include the diagram rather than a desription......
f(x) = sqrt(x+2) -1
f' = 1/ (2(sqrtx+2)) at x = 2 this will give you the slope AT x=2 1 /(2(sqrt2+2)) = 1/4
Yah...now I can see it.....Here ya go:
NOW the area can be calculated as
the area of the RECTANGLE (6.5 x 6) + the area of the two small triangles 2* 1/2 (2.5*6)
6.5 * 6 + 2 * 1/2(2.5 * 6) = 54 sq yds
54 yd^2 / 15 yd^2/bag = 3.6 bags He will need 4 bags
Select the Image function.....then upload image......
