EmeraldWonder

De nada, solo feliz de ayudar te

;P

OOOOHHHHH You cant be stealling my trademark, doesn't matter though you used it wrong.

;P

$9+(\frac{1}{2})^4*48$

Find what $(\frac{1}{2})^4$ equals:

$(\frac{1}{2})^4$

$\frac{1^4}{2^4}$

$\frac{1}{2^4}$

Then $48 * \frac{1}{2^4}$

$\frac{1*48}{2^4}$

$\frac{48}{2^4}$

Factor 48 which will come to $2^4 * 3$

$\frac{2^4 * 3}{2^4}$

$3$

Now continue

$9 + 3$

$12$

Your answer would be 12

Hope this Helps ;P

I see you put the wrong photo, alright I can take care of that on 13

Why dont you ask that separately?

Yep, just a malfunction I guess, but no one writes in pink ;P

You just asked this question and I just answered it:

Your welcome ;P

If you replace the varaibles you will get:

$\frac{1}{3}(3^2)+5.2(2)$

First complete: $\frac{1}{3}(3^2)$

$\frac{1*3^2}{3}$

$\frac{3^2}{3}$

$3$

Then complete: $5.2(2)$

$5.2(2)$

$10.4$

Now you have:

$3+10.4$

$13.4$

Your answer is 13.4

Hope this Helps ;P

I forgot to remove the square at the end. I redited my work to put the correct end result, thank you for correcting me, I see my error

;P