EmeraldWonder

De nada, solo feliz de ayudar te

;P

OOOOHHHHH You cant be stealling my trademark, doesn't matter though you used it wrong.

;P

\(9+(\frac{1}{2})^4*48\)

Find what \((\frac{1}{2})^4\) equals:

\((\frac{1}{2})^4\)

\(\frac{1^4}{2^4}\)

\(\frac{1}{2^4}\)

Then \(48 * \frac{1}{2^4}\)

\(\frac{1*48}{2^4}\)

\(\frac{48}{2^4}\)

Factor 48 which will come to \(2^4 * 3\)

\(\frac{2^4 * 3}{2^4}\)

\(3\)

Now continue

\(9 + 3\)

\(12\)

Your answer would be 12

Hope this Helps ;P

I see you put the wrong photo, alright I can take care of that on 13

Why dont you ask that separately?

Yep, just a malfunction I guess, but no one writes in pink ;P

You just asked this question and I just answered it:

Your welcome ;P

If you replace the varaibles you will get:

\(\frac{1}{3}(3^2)+5.2(2)\)

First complete: \(\frac{1}{3}(3^2)\)

\(\frac{1*3^2}{3}\)

\(\frac{3^2}{3}\)

\(3\)

Then complete: \(5.2(2)\)

\(5.2(2)\)

\(10.4\)

Now you have:

\(3+10.4\)

\(13.4\)

Your answer is 13.4

Hope this Helps ;P

I forgot to remove the square at the end. I redited my work to put the correct end result, thank you for correcting me, I see my error

;P