It did!
Thanks
\({\sqrt{72} \over \sqrt{25}}\)=\({ \sqrt{3^2*2^2*2} \over 5}\)=
\( {6\sqrt{2} \over 5}\)
Your question is not complete
the formula for finding the area of a trapezoid is A = (1/2)(h)(b1 +b2)
with b1 = 6 and b2 = 16
can you figure out the rest?
