Given that \((-2,3)\) is on the graph of \(y=f(x)\), find a point on the graph of \(y=f(2x+1)+3\). Express your answer as an ordered pair \((a,b)\) where \(a\) and \(b\) are real numbers.

I've always had trouble with these kind of problems, so could someone explain it thoroughly please?

Thanks in advance.

FeedMePi Aug 24, 2021

#1**+4 **

Hello Pi :))

I really want pie after seeing your pfp.

We know that f(-2) = 3.

So we should make the 2x + 1 = -2 on the graph y = f(2x + 1) + 3.

2x + 1 = -2

2x = -3

x = -1.5

y = f(2x + 1) + 3

y = f(2(-1.5) + 1) + 3

y = f(-2) + 3

f(-2) = 3

y = 3 + 3

y = 6

(-1.5, 6)

I hope this helped.

=^._.^=

catmg Aug 24, 2021