+0  
 
+1
59
2
avatar+71 

Given that \((-2,3)\) is on the graph of \(y=f(x)\), find a point on the graph of \(y=f(2x+1)+3\). Express your answer as an ordered pair \((a,b)\) where \(a\) and \(b\) are real numbers.

 

I've always had trouble with these kind of problems, so could someone explain it thoroughly please?

Thanks in advance.

 Aug 24, 2021
 #1
avatar+2207 
+4

Hello Pi :))

I really want pie after seeing your pfp. 

 

We know that f(-2) = 3. 

So we should make the 2x + 1 = -2 on the graph y = f(2x + 1) + 3. 

2x + 1 = -2

2x = -3

x = -1.5

 

y = f(2x + 1) + 3

y = f(2(-1.5) + 1) + 3

y = f(-2) + 3

f(-2) = 3

y = 3 + 3

y = 6

(-1.5, 6)

 

I hope this helped. 

=^._.^=

 Aug 24, 2021
 #2
avatar+71 
+4

It did!

Thanks

smiley

FeedMePi  Aug 24, 2021

12 Online Users

avatar