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Simplify $\frac{\sqrt{72}}{\sqrt{25}}$. Your answer should have an integer denominator.

 Aug 22, 2021
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\({\sqrt{72} \over \sqrt{25}}\)=\({ \sqrt{3^2*2^2*2} \over 5}\)=

\( {6\sqrt{2} \over 5}\)

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 Aug 22, 2021

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