geno3141

k·1984·2  can be written as  k·3968  =  k·27·31

27·31  has these 16 factors: 

        1, 2, 22, 23, 24, 25, 26, 27,

        31, 31·2, 31·22, 31·23, 31·24, 31·25, 31·26, and 31·27  

If k is a number such as 3, another 16 factors will be created (3 times each of the previous 16 factors).

If k is 2, two more factors are created, 28  and  31·28, for a total of 18 factors.

If k is 4 = 22, another two factors are created:  29  and  31·29, for a total of 20.

If k is 8 = 23, another two factors are created:  210  and  31·210, for a total of 22.

If you don't exclude 1 as a factor, I don't know how to get exactly 21.

Point-slope equation:  y - y₁  =  m(x - x₁)

m is the slope:  m = 3/2

(x₁, y₁) is the point:  x₁ = 7  and  y₁ = 4

Place the values into the equation and simplify.

"At most one will arrive late" means that either:

1)  all will arrive on time, or

2)  one will be late.

The probability that any one plane arrives on time is 1.00 - 0.22  =  0.78.

1)  all ten arriving on time  =  (0.78)¹⁰

2)  one will be late but nine arrive on time  =  10 x (0.22)¹ x (0.78)⁹

          [the factor of 10 is used because the one that arrives late can be

           the first plane or the second plane or ... the tenth plane; ten ways]

To get the final answer, calculate the two individual probabilities and add them together.

The calculator at this site will give you the answer.

Rule:  a₁  =  16          a_n  =  ½·a_{n - 1}  

a₁  =  16  =  2⁴

a₂  =    8  =  2³

a₃  =    4  =  2²

a₄  =    2  =  2¹ 

Notice that each answer can be written as a power of 2.

Also notice that the subscript of the term when added to the exponent results in 5.

Combining these two ideas:  a_n  =  2^{5 - n}

...

Find the median of the original set and multiply it by 26

or: 

multiply each of the original numbers by 26 and find the median of this new set of numbers.

0.6 x 3.50  +  1.8 x 2.50  =  6.60

x³ - x² - x  =  x(x² - x - 1)  =  x(0)  =  0

a/c  =  [ a/b ] / [ c/b ]  =  [ sqrt(10) / sqrt(21) ] / [ sqrt(15) / sqrt(14) ]

                                  =  [ sqrt(10) · sqrt(14) ] / [ sqrt(21) · sqrt(15) ] 

                                  =  [ sqrt(10) / sqrt(15) ] · [ sqrt(14) / sqrt(21) ]

                                  =  [ sqrt(2) / sqrt(3) ] · [ sqrt(2) / sqrt(3) ]

                                  =  2/3

The left-hand limit is 0.

The right-hand limit is -5.