ABN+NBC=ABC so we substitute the given values of each angle.
23x+63x+3=175
86x+3=175
86x=172
x=2
The two segments HI and IJ must add up to the length of the HJ. So we have the equation:
3x-5+(x-1)=7x-27
4x-6=7x-27
3x=21
x=7
Ah never mind, I've got it.
The distributive property.
Move everything to make it a quadratic equaation:
x^2-4x=5
x^2-4x-5=0
Factor and solve for x:
(x-5)(x+1)=0
x=5, -1
The 1st statement is true. Any of the other two angles that are not the third angle equal to the supplement of the third angle. So angle 1 and 2 add up to be equal to angle 4, which is angle 3's supplement.
Ah that makes much more sense. Thank you guest!
You're welcome!
Let x be the number of adult tickets sold. Then the number of children tickets sold is 275-x. Now we form an equation to represent the total money made from selling the tickets.
14x+6(275-x)=2458
14x+1650-6x=2458
8x+1650=2458
8x=808
x=101.
If a number were less than -3, the only possible choice is -5. There are no options here greater than 5 though, so it is not possible.
Although I believe the problem should be phrased "Which number is less than -3 and greater than 5."
+781 