https://web2.0calc.com/questions/help-with-proof

I found this and everything makes sense.

But I don't understand how CPhill got to 2xh + 2yh = 2ab . I tried working out and expanding the given equation in the problem and using the triangle similarity he provided in an attempt to get what he got, but I don't understand how. Does anyone understand and can explain this part to me? Thank you!

gwenspooner85 Jul 6, 2020

#1

#3**+1 **

In the original post, there was this equation:

x^{2} + 2xh + h^{2} + y^{2} + 2yh + h^{2} = x^{2} + h^{2} + 2ab + y^{2} + h^{2}

Subtract x^{2}, h^{2}, y^{2}, and h^{2} from both sides and you are left with: 2xh + 2yn = 2ab

geno3141 Jul 6, 2020

#4**+1 **

Oh I see...I didn't see the OP's working. However, I don't understand how the equation leading back to h/a=b/(x+y) proves that (x+h)^2+(y+h)^2=(a+b)^2.

gwenspooner85
Jul 6, 2020