The two factors of the first number that you are looking for is 11 and 5.
We first prime factorize 55, and we get 5 * 11.
So we can immediately test 5 and 11.
5 * 11 = 55 and 5 + 11 = 16.
it works!
i hope this helped.
I don't think this was a very good question, because you can solve it even if the two numbers aren't integer factors of 55!
The idea is to find two numbers p and q such that
p+q=16
and
pq=55
The trick is to observe that if in the quadratic equation
ax2+bx+c=0
the two roots are p and q then we can put x2+bx+c≡(x−p)(x−q)
and therefore a=1, b=−(p+q), c=pq.
It follows that p and q are the two roots of the equation x2−16x+55=0.
You can solve this simply by "spotting" the roots or by turning the handle of the sausage machine:
x=−b±√b2−4ac2a=16±√162−4×552=8±3
Obviously this will work even if b doesn't have integer factors!