Suppose p varies directly with d, and p = 2 when d = 7. What is the value of d when p =10?
d = kp
Since d = 7 when p = 2, we can solve for k
7 = 2k
k = 2/7
so the equation is d = 2/7 p
When we plug in 10 for p, it becomes
d = 2/7 * 10
= 20/7
2. Just plug in 2. T(2) = 2 * 8 = 16
3. The absolute value doesn't matter in this one because you're plugging 4 for x, and 4 is a positive number.
f(4) = |4| * 7 = 28
