Algebra help.

2/7=10/d

d=35

* scratches head*

Umm...

Suppose p varies directly with d, and p = 2 when d = 7. What is the value of d when p =10?

d = kp 
Since d = 7 when p = 2, we can solve for k 
7 = 2k 
k = 2/7 
so the equation is d = 2/7 p 
When we plug in 10 for p, it becomes 
d = 2/7 * 10 
= 20/7 

2. Just plug in 2. T(2) = 2 * 8 = 16 

3. The absolute value doesn't matter in this one because you're plugging 4 for x, and 4 is a positive number. 
f(4) = |4| * 7 = 28

:P             

^.-...

Your answer is correct Solveit.    

Hayleys method is also correct and it is the way I do it but

Haylyey found    

  p when d=10 insteads of finding

What is the value of d when p =10     :)