An airplane travels 460 miles from San Diego to San Francisco in 2.5 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.
The airplane flies at 207 mi/h with no wind. The rate of the wind is 23 mi/h.
The airplane flies at 230 mi/h with no wind. The rate of the wind is 184 mi/h.
The airplane flies at 207 mi/h with no wind. The rate of the wind is 11.5 mi/h.
The airplane flies at 184 mi/h with no wind. The rate of the wind is 230 mi/h.
+8581 I will not accept them! They are your stars :)
* Crumbles my paper*
Forget it! haha
460 / 2.5 =184mph travelling against the wind
460 / 2 =230mph travelling with the wind
230 - 184=46 / 2 =23mph rate of the wind
[230+184] / 2 =207mph rate of the plane without wind.
So, the answer is:
The airplane flies at 207 mi/h with no wind. The rate of the wind is 23 mi/h.
+129850 Here's another way to do this:
D/R = Time [ in hours] so
Call the rate of the wind, w and the plane's normal rate, p
So we have.....when the plane is flying with the wind.....
460/ [p + w] = 2
230/[p+ w] = 1
230 = p + w
p = 230 - w
And when the plane is against the wind, we have
460 / [p - w] = 2.5
184 / [ p - w] = 1 subbing in for p, we have
184/ [ 230 - w - w] = 1
184 = 230 - 2w
2w = 230 - 184
2w = 46
w = 23 mph
And the plane's normal rate = 230 - 23 = 207 mph
