HELPMEEEEEEEEEEEEE

Left out brackets?

Let x be the speed for the first two miles and x+.5 be the speed for the last 8 miles. Since D=rt, \(2\over x \)+\(8\over x+.5\)is the time it took Janet to do the 10 mile race. If she took her bike the whole way, her time would be \(10\over x+.5\). Since that was two minutes faster than her real time, \(2\over x \)+\(8\over x+.5\)-\(10\over x+.5\)=2. Solving for s you get s=.5. The question asks for the average speed for the whole race so, \(2\over .5\)+\(8\over .5+.5\)=\(10\over a\) where a is the average speed. A= \(5\over 6\) miles per minute.

Hope it helps!

Plugging in "x-15" into f(x)= 1/9x^2, 1/9(x^2-30x+225)=

\(x^2-30x+225\over9\)

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I changed the last root which I believe my answer is now correct.

Did you try sketching a diagram to get a visual of what it looks like?

First convert (x+4)(x-8) to quadratic form which makes it x^2-4x-32. From there "Complete the square" which makes it y+32=x^2-4x...y+36=(x-2)^2.

Then you add 36 to both sides to get y=(x-2)^2-36 which is your answer.

Hope it helps!

The polynomial factors into (X-1)(X^2+2x-1) which gives us the roots X= 1, X= -1+sqrt2, and X= -1-sqrt2. The "sqrt" means square root.

Hope it helps!

Let's call the blue marbles x and white marbles 2x+9. That means that 3x+9= 57. solving for x, you get x= 16. This means that 16 marbles are blue which means 41 marbles are white.