Suppose f(x)=1/9x^2.
find a formula for y = f(x-15) in terms of the variable x.
y=f(x-15)=
Plugging in "x-15" into f(x)= 1/9x^2, 1/9(x^2-30x+225)=
\(x^2-30x+225\over9\)
Hope it helps!
I apologize helpmeeeeeee
You did not.
I think the asker may have though.
1/9x^2 = \(\frac{1}{9}*x^2\) (as helpmeeeee interpreted it)
but I think the asker may have meant
1/(9x^2)
Maybe he/she didn't but we are so used to seeing brackets used poorly that we often surmise what is wanted.
For that reason, it is a good idea to put brackets in even when they are not strictly necessary.
It cuts down on confusion.
Perhaps in this instance, it is me that is wrong, but still, I hope I give readers something to think about.