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# Helpmeeeee

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Suppose f(x)=1/9x^2.

find a formula for y = f(x-15) in terms of the variable x.

y=f(x-15)=

Apr 7, 2020

#1
+932
+2

Plugging in "x-15" into f(x)= 1/9x^2, 1/9(x^2-30x+225)=

$$x^2-30x+225\over9$$

Hope it helps!

Apr 7, 2020
#2
+109520
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Both of you have left out brackets.

Apr 7, 2020
#3
+932
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Left out brackets?

HELPMEEEEEEEEEEEEE  Apr 7, 2020
#4
+109520
+1

I apologize helpmeeeeeee

You did not.

I think the asker may have though.

1/9x^2 = $$\frac{1}{9}*x^2$$      (as helpmeeeee interpreted it)

but I think the asker may have meant

1/(9x^2)

Maybe he/she didn't but we are so used to seeing brackets used poorly that we often surmise what is wanted.

For that reason, it is a good idea to put brackets in even when they are not strictly necessary.

It cuts down on confusion.

Perhaps in this instance, it is me that is wrong, but still, I hope I give readers something to think about.

Apr 7, 2020
#5
+932
+1

Ok thanks for the clarification!

HELPMEEEEEEEEEEEEE  Apr 7, 2020