HELPMEEEEEEEEEEEEE

Again, we need the measure of the radius to find the length of the arc. I'm not sure if the 8's are part of your question, but if so, the arc length is 4*3.14= 12.56. If the 8's are not part of your question, you need to find the radius of the circle that the problem gave you. Finding the arc length was already explaing twice now.

Hope it helps!

That is a great observation! If that is the pattern, then you should be able to solve the problem from there!

The first quadratic does not factor so we can skip that one for now...

The second quadratic factors into 3(x+7)(x−8) which doesn't have any repeating roots so this is not the answer.

The third quadratic does not factor so we can skip that one for now...

The fourth quadratic factors into (5x−3)(5x−3) which has repeating roots so this is our answer.

The fifth quadratic factors into (x−2)(x−12) which doesn't have any repeating roots so this is not the answer.

Hope it helps!

I'm not seeeing any pattern here, so we should probably look for something else...

For this problem, we wouldn't need the y-intercept, so we could go straight from the information to construct of final answer instead of having to make an equation in slope-intercept form.

Given the point (3, 9) and the slope of 2, we get y-9= 2(x-3) which is your answer in point-slope form.

There are 10 arrangements if a is 11...

For b., if a were 13 then there is one arrangement where all of them are 13, if a were 12 then there are 4 arragements... I wonder if there is a pattern.

Yeah I just saw that...