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A line with a slope of 2 passes through the point (3,9).  Write an equation for this line in point-slope form.

 Apr 7, 2020
 #1
avatar+932 
+1

Given the point (3, 9) and the slope of 2, we get y-9= 2(x-3) which is your answer in point-slope form.

 Apr 7, 2020
 #2
avatar+50 
+2

I'm going to answer the solution in Point-Slope and Slope-Intercept. 

 

Slope - Intercept form is this: y = mx + b

We know that (x, y) is a point on the line, m is the slope, and b is the y-intercept. 

 

From the given information we have that it has a slope of 2 (m = 2), and one of the points on the line is (3, 9) which means that (x = 3, y = 9)

Plugging in we get:

 

y = mx + b

9 = 2*3 + b

9 = 6 + b

b = 3

Therefore the y-intercept is 3. After having this information we can construct our equation.

 

We now have to put this in the point-slope form which is: (y - y1) = m(x - x1)

Transferring what we had before we can plugin and get y - 9 = 2(x - 3)

 

Comment down if you have any queries or any questions on the solution. Tell me as soon as possible. Good luck in your Algebra Pursuit!! :)

Enjoy!! I put the answer in both point-slope and slope-intercept if you haven't noticed!! :)

So our answer is:

y - 9 = 2(x - 3)​

 Apr 7, 2020
 #3
avatar+932 
+1

For this problem, we wouldn't need the y-intercept, so we could go straight from the information to construct of final answer instead of having to make an equation in slope-intercept form.

HELPMEEEEEEEEEEEEE  Apr 7, 2020
 #4
avatar+50 
+2

Yeah, I knew that but accidentally misread the question, but I decided to post both for the viewer's knowledge. 

KingHTML  Apr 7, 2020
 #5
avatar+932 
0

That's good. smiley

HELPMEEEEEEEEEEEEE  Apr 7, 2020

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