A line with a slope of 2 passes through the point (3,9). Write an equation for this line in point-slope form.
Given the point (3, 9) and the slope of 2, we get y-9= 2(x-3) which is your answer in point-slope form.
I'm going to answer the solution in Point-Slope and Slope-Intercept.
Slope - Intercept form is this: y = mx + b
We know that (x, y) is a point on the line, m is the slope, and b is the y-intercept.
From the given information we have that it has a slope of 2 (m = 2), and one of the points on the line is (3, 9) which means that (x = 3, y = 9)
Plugging in we get:
y = mx + b
9 = 2*3 + b
9 = 6 + b
b = 3
Therefore the y-intercept is 3. After having this information we can construct our equation.
We now have to put this in the point-slope form which is: (y - y1) = m(x - x1)
Transferring what we had before we can plugin and get y - 9 = 2(x - 3)
Comment down if you have any queries or any questions on the solution. Tell me as soon as possible. Good luck in your Algebra Pursuit!! :)
Enjoy!! I put the answer in both point-slope and slope-intercept if you haven't noticed!! :)
So our answer is:
y - 9 = 2(x - 3)
For this problem, we wouldn't need the y-intercept, so we could go straight from the information to construct of final answer instead of having to make an equation in slope-intercept form.
Yeah, I knew that but accidentally misread the question, but I decided to post both for the viewer's knowledge.