hipie

First, you simplify the sides, pretty straightforward you get x^2 - 3x + 4. Keep in mind that the sum of the roots = -b/a and the product of the roots = c/a. I will put r_1 as a, and r_2 as b. so a + b = -3, and ab = 4. Solve the systems and sub in for a^3 * b + a* b^3

You should solve it by finding the horizontal asymptope once you graphed the function. Don't worry, it should be pretty simple. 

I'm not a guest?

They are just people who just answer randomly to questions, and that is literally what makes these websites untrustworthy. This can, for example, make people not understand a math subject. 

Simplify $$(1-3i)(1-i)(1+i)(1+2i)(1-4i) \ is \ 6 - 58i$$

get your latex right please

I can tell this is wrong immediately. If you sub in x for 0, it would end up with 6, not 4. There are so many wrong answers that guests make, and on purpose. Can anyone just say how to fix this?

they didn't do their latex correctly, it was $\frac{x}{4} - \frac{y}{5}=1$

$\displaystyle g(x)=\sqrt[3]{\frac{x+3}{4}}$, for what value of x will g(2x) = g(x)? x=0

$\frac{a}{b} = \frac{3}{5}, \frac{b}{c} = \frac{6}{15},\space and\quad \frac{c}{d} = \frac{1}{6}. \ \textcolor{red}{What \ is \ the \ value \ of \frac{a}{d}}?$

Explain.

Why did you like your comment when you got it wrong?