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What is the slope of a line perpendicular to the line whose equation is $\frac{x}4-\frac{y}5=1$? Express your answer as a common fraction.

 Jul 17, 2022
 #1
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Believe it or not, I don't speak LaTex cheeky

 Jul 17, 2022
 #4
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they didn't do their latex correctly, it was \(\frac{x}{4} - \frac{y}{5}=1\)

hipie  Jul 18, 2022
 #2
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Ok!

 

What is the slope of a line perpendicular to the line whose equation is (x/4)-(y/5)=1? Express your answer as a common fraction.

 Jul 17, 2022
 #3
avatar+2448 
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We have this equation: \(\frac{x}4-\frac{y}5=1\)

 

Subtract \({x \over 4}\) from both sides: \(-{y \over 5} = 1 - {x \over 4}\)

 

Multiply the entire equation by -5: \(y = {5 \over 4} x - 5\)

 

This means that the slope is \({5 \over 4}\), the slope of the line that is perpendicular to this is the negative reciprocal, or \(\color{brown}\boxed{-{4 \over 5}}\)

 Jul 17, 2022

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