ItzMe

Number of total cards in the deck = 52. Number of face cards in the deck = 12. Now, we need to find the number of ways such that the first card is always a face card. Now, first card is face card so number of cards left to be arranged = 52 - 1 = 51. We take the factorial of that so we can find out how many diffrent ways we can re-arange them, but them we have to multiply it by 12, beacus of the 12 face cards we can hoose from.

Im not 100 percent sure, but i think the answere should be 51!*12, pls tell whether it right or not.

So we can express jacks curent age as x, and bao's current age as x-13. It says that 'In 8 years, he will be twice as old as Bao" and we can express that as x+8=2(x-13+8) which we can simplify to x+8=2x-10 from here x=18, so jack is curently 18.

Yes, thank you.

Thank you so much. :)

I am really, sorry it was an acident, I will try to delet this post. Sorry.

Ok, Thankyou so much for your help :)

Thankyou so much :)

It doesn't show me how many cubes its cut into, that's all that I see, sorry

No, it says that its correct, thank you 

If we wanted to fingd the last digit, we would have to go threw the endings of the powers of 7

7^1=7

7^2=9

7^3=3

7^5=1

7^6=7

So from here the cycle repeats every 4. 

2017 divided by 4 leaves a remainder of 1, so the last digit is 7. 

But the question asks for the last 10 and first 10 digits, and i have no idea how to solve that, I don't think that it is really posible, it would leave a huge number.

Sorry if this post was unhelpful, but I don't think that the solution is possible (I mean, it is possiblr, but, like I said befor, it would end up as a huge number that would be really hard to calculate, and I don't think there are any meathods or short cut). Once agian, sorry,