Three clever monkeys divide a pile of bananas. The first monkey takes some bananas from the pile, keeps three-fourths of them, and divides the rest equally between the other two. The second monkey takes some bananas from the pile, keeps one-fourth of them, and divides the rest equally between the other two. The third monkey takes the remaining bananas from the pile, keeps one-twelfth of them, and divides the rest equally between the other two. Given that the pile starts out with a positive number of bananas, each monkey receives a whole number of bananas whenever the bananas are divided, and the numbers of bananas the first, second, and third monkeys have at the end of the process are in the ratio , what is the least possible total for the number of bananas?

ItzMe Jun 24, 2020

#1**0 **

https://artofproblemsolving.com/wiki/index.php/2004_AIME_II_Problems/Problem_6

Go to this site, please do not post aops questions, please ask for hints and tell us your steps. This can not be a place where you just get free answers, please read through the link and understand! Ask the message board for help

sarvajitjjjj Jun 24, 2020