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Compute the sum of all positive integers k for which the number k*1984 has exactly 21 positive divisors.

 Jun 24, 2020
 #1
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1984 =  2^6 * 31

 

Just multiply 1984 x 31 =(1, 2, 4, 8, 16, 31, 32, 62, 64, 124, 248, 496, 961, 992, 1922, 1984, 3844, 7688, 15376, 30752, 61504) >>Total = 21 divisors

 

 

31 =3 + 1 =4

 Jun 24, 2020
 #2
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Thankyou so much :)

 Jun 24, 2020

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