your welcome
we do 10*9*8*7=5040 so there are 5040 ways to choose
(16sqrt3)/3 since QT=QR=8
so we have 13*8=104 which is the smallest 3 digit multiple of 13 and then we have 13*77 but that is more than 1000 might be what you are thinking but we have a purpose for that ecuase we are doing 77-8=69 so there are 69 multiples of 13 that are 3 digit numbers
well we get slope 1/2 and we find points -1,2 and 2.2,0.4 to inersect w ethen use the pythangorean theorem to find the coorinates of midpoint AB is 3/5, -6/5
we get C(15,5) and C(15,5)=3003 then we divide by the overlaing parts to get 3003/33=91 but we have to subtract 20 to get 71 ways
x=−a+√[(a−2)(a+5)]
x=−a−√[(a−2)(a+5)]
so x can be anything when x^(2) + 2ax- 3a >-10 is true where we substitute x with the equation above to get x=(-5)<=>(2)
if x=1 then it equals 1.0173001 if x=2 then it equals 1.03429032 an dif x=1000 then it equals −0.81115957 and if x=pi/4 then it equals sqrt2 which is the largest
there is NO square roots for negative numbers
