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# Help

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597
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How do we solve log things?

Jun 9, 2020
edited by Guest  Jun 9, 2020
edited by jimkey17  Jun 9, 2020
edited by jimkey17  Jun 9, 2020
edited by jimkey17  Jun 9, 2020

#1
+2

Hi.

Logarithmic functions are the inverse of exponents, which means...

an exponent, say a^b, is b number of a's multiplied together.

On the other hand.

Loga (b) is asking a to the what power is b?

So we are solving for x where a^x = b.

Thus, say, log. base 10(this is the "a") of 1000, is 10^x = 1000, x = 3.

Log2 (8) = 3.

If you don't understand anything feel free to ask!

Jun 9, 2020
#2
+22

Thanks a lot

jimkey17  Jun 9, 2020
#3
+2

In mathematics, the logarithm is the inverse function to exponentiation. That means the logarithm of a given number x is the exponent to which another fixed number, the base b, must be raised, to produce that number x.

For example, 10^3 = 1,000; therefore, log10 1,000 = 3.

Jun 13, 2020
#4
+3

Yeah I knew logs aleady thanks though log2(2048)=11

Jun 18, 2020
edited by jimkey17  Jun 18, 2020