Yes. here's a T-table of x's and y's
x | y (decimal expansion) |
1 | 1 /1 (1.000000...) |
2 | 3 /2 (1.500000...) |
3 | 11 /6 (1.833333...) |
4 | 50 /24 (2.083333...) |
5 | 274 /120 (2.283333...) |
6 | 1764 /720 (2.45...) |
7 | 13068 /5040 (2.592857...) |
8 | 109584 /40320 (2.717857...) |
9 | 1026576 /362880 (2.828968...) |
So I figured out the x! goes on the denominator. I'm not sure about the numerator.
But I noticed this pattern: to get the numerator for y, take the numerator of (y-1), multiply it by x, then add (x-1)!
Any help is appreciated!