lynx7

(i) n(n-1)

    If n-1 is odd, then n is even. 
    n(n-1) is the product of an even number and an odd number, so the product is even.

(ii) 2n=2*n Multiplying any whole number by 2 gives an even number, so 2n is an even number. So 2n+1=even number +1=odd number 2n+1 must always be an odd number.

what is it?

√ [ 567 * x^2 * y^4 * z^2] 

√567 * √x^2 * √y^4 * √z^2

9 * √7 * √x^2 * √y^4 * √z^2

9 * √7 * x * y^2 * z

9xy^2z√7

(9xy^2z√7)^2

=81x^2y^4z^2*7

d is directly proportional to the square of t 

d=k*t^2

80=k*4^2

80=k*16

k=80/16

k=5

d=5*t^2

8+4=12

d=5*12^2

d=5*144

d=720m

question 1:

2/n

question 2:

15

thanks cphill see you in the afternoon

the answer is 87 if you turn your head upside down the numbers are going by step

thank cphill

answer:

the second table shows an inverse variation

explanation:

Only the second table has pairs whose product is always the same value (60).

answer:84.3%