$${\mathtt{121}}{\mathtt{\,\times\,}}{\mathtt{121}} = {\mathtt{14\,641}}$$
Since theirs different types of A does that mean AABBB and AABBB could be different.
AABBB
ABBBA
BBBAA
BABAB
BAABB
BABBA
ABABB
ABBAB
BBABA
um... >.<
5!/(2!×3!)
1*2*3*4*5=120
1*2=2
1*2*3=6
is it 120 divided by 6 * 2 ? $${\frac{{\mathtt{120}}}{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{2}}\right)}} = {\mathtt{10}}$$
