MathsGod

$${\mathtt{121}}{\mathtt{\,\times\,}}{\mathtt{121}} = {\mathtt{14\,641}}$$

$${\mathtt{121}}{\mathtt{\,\times\,}}{\mathtt{121}} = {\mathtt{14\,641}}$$

Since theirs different types of A does that mean AABBB and AABBB could be different.

AABBB

ABBBA

BBBAA

BABAB

BAABB

BABBA

ABABB

ABBAB

BBABA

um... >.<

 5!/(2!×3!)

1*2*3*4*5=120

1*2=2

1*2*3=6

is it 120 divided by 6 * 2 ?  $${\frac{{\mathtt{120}}}{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{2}}\right)}} = {\mathtt{10}}$$