MIRB14

ANYWAYS... here's the answer if you don't want to do it

Simplify the original line: We get y=-(2/3)x+8

The line parallel to another line has the same slope.

Therefore, our line would be y=-(2/3)x+b, b being the y-intercept.

We also know that the line passes through point (12,-4). We can substitute the points into the line equation to solve b.

We get -4=-(2/3)*12+b => -4=-8+b => b=4

The line is y=-(2/3)x+4

Check it by using desmos.com

The formula for a circle is (x – h)^2 + (y – k)^2 = r^2.

Now we just make the formula into our problem: (x-7)^2+(y-8)^2=10^2

Then we substitute (13,16) into the formula. If the solution is right, then (13,16) is on circle O. If not, then it's not.

(13-7)^2+(16-8)^2=100

6^2+8^2=100

36+64=100

100=100

This equation is true, so the answer is yes.

Mathisfornerds, please, instead of making so many topics, put all of your questions in a numbered list for one topic.

Your question is similar to your other questions, just change the equation into slope-intercept form and do the samething and do the samething I did for your other question.

The line parallel to another line has the same slope.

Therefore, our line would be \(y=\frac{1}{4}+b\), b being the y-intercept.

We also know that the line passes through point (-8,-7). We can substitute the points into the line equation to solve b.

We get \(-7=\frac{1}{4}\times-8+b\Rightarrow-7=-2+b\Rightarrow b=-5\)

The line is \(y=\frac{1}{4}x-5\)

Check it by using desmos.com

Question answered here: https://web2.0calc.com/questions/math-postage-stamp-problem

Yes, press shift+backslash to make this: |

Surround a number with the absolute value signs, such as this: |-2|

The calculator should spit out 2

Thanks!

Thanks!

If you're using a mac, you can do alt+< or > to get ≤ or ≥