MooMooooMooM

wow i saw it,

same answer, kind of the same explantion,

Great mind do think alike!

The integers between -12.1 and 3.3 are -12 to 3.

We can add the negatives and the positives separately.

1+2+3 is 6.

1+2+3+4+5+6+7+8+9+10+11+12 is 78, so the negatives would equal -78.

-78+6 is -72.

If the median of an even number of distinct integers is ten, then the two middle numbers have to sum to 20.

Making them 9 and 11 would be ideal so we can use the rest of the small one-digit numbers for the below numbers and the small two-digit numbers directly above 11(what I'm saying is using these numbers will minimize the other numbers)

To minimize the others, we make them 1, 2, 3, 4, 9, 11, 12, 13, 14, and 15.

The average of those numbers is 84/10 or 8.4.

If they are multiples of both 4 and 6, they will be the multiples of lcm(4,6) = 12.

The multiples of 12 that are less than 100 are

12, 24, 36, 48, 60, 72, 84, 96.

So there are 8 numbers.

15/2 = 7.5

Adding multiples of 2 we can never get 1/2 unless we use an exponent of -1 at one point.

Having exponents smaller would result in longer decimals(.25,.125) So x has to be -1

Checking we get

2^-1+2^0+2^1+2^2

1/2+1+2+4

1/2+7

7.5

If EG is 5/3 the length of EF, then say EG is 5 centimeters and AF is 3 centimeters.

Then FG is 2 centimeters.

HF is 5 times that or 10 centimeters.

We know FG is 2 so HG is 8.

So EF/HG is 3/8

Thanks for pointing that out guest...

98/18 or 49/9

18/14 equals 7/x.

Cross multiplying we get 91=18x

x=91/18

2(x+1.5)^2+6.5

(a+b)^2=a^2+2ab+b^2

(x+1.5)^2=x^2+3x+2.25

Times 2

2x^2+6x+4.5+6.5=2x^2+6x+11

h is 1.5

f(6) would be -1/6

doing that again gives us -1/(-1/6) or 6 again.

So every two times we use the function they cancel each other out.

So the first four functions are ignored

So all we have is f(6) as the answer