Points $E$, $F$, $G$, and $H$ lie on a line in that order. If $EG=\frac{5}{3}EF$ and $HF=5FG$, then what is $\frac{EF}{HG}$?
+539 If EG is 5/3 the length of EF, then say EG is 5 centimeters and AF is 3 centimeters.
Then FG is 2 centimeters.
HF is 5 times that or 10 centimeters.
We know FG is 2 so HG is 8.
So EF/HG is 3/8
+539 If EG is 5/3 the length of EF, then say EG is 5 centimeters and AF is 3 centimeters.
Then FG is 2 centimeters.
HF is 5 times that or 10 centimeters.
We know FG is 2 so HG is 8.
So EF/HG is 3/8
