mworkhard222

I'm pretty sure he/she copied it from somewhere, I think it should be $16c^4-16c^{12}.$

yeah thx, i got it, its 120

Well we can simplify both of them starting with √50.

$\sqrt{50}$

$=\sqrt{2\cdot \:5^2}$

$=\sqrt{2}\sqrt{5^2}$

$=5\sqrt{2}$

$\sqrt{18}$

$=\sqrt{2\cdot \:3^2}$

$=\sqrt{2}\sqrt{3^2}$

$=3\sqrt{2}$

So adding $3\sqrt{2}+5\sqrt{2},$ you get $8\sqrt{2}$

oh thats wut u mean, lemme fix it

i'm kinda sick but one of my relative answered it here:

first of all, welcome to webcalc 2.0!

1. solve this system of equations: x+y = 10, xy = 16, you get $x=8, \: y=2$. 8 - 2 = 6. keep in mind that you could do 2 - 8 and get -6 as well.

idk if this is right, here's my best shot.

this is just a system of equations:

$\begin{pmatrix}x=5+\sqrt{69},\:&y=5-\sqrt{69}\\ x=5-\sqrt{69},\:&y=5+\sqrt{69}\end{pmatrix}$

$\frac{y}{3}+1=\frac{y+3}{y}$

$y^2+3y=3\left(y+3\right)$                          (multiply both sides by 3y)

$y^2+3y=3y+9$                              (distribute right side)

$y^2=9$                                                 (subtract both sides by 3y)

$y=3,\:y=-3$                                  (final answer)