Nacirema

It could also be the next term is the last term raised to the power of 4 times 4... 

1, 4, 1024, 4398046511104

There are simply too many options to concider, do you mind telling us what the pattern is?

That should be correct! 

Assuming you want to know the circumference, we are given the area is $88\pi.$

Now we have to take it and set it equal to the area of a circle's equation. 

$r^2\pi = 88\pi\\\implies r^2=88\\\implies r=\sqrt {88}\\\implies r=2\sqrt {22}$

The crcumference of a circle is $2\pi\cdot r\\\implies \boxed {4\sqrt{88}\pi}$

You never know, it might just come in handy down the line!

My bad, I had a typo in there. I corrected my answer. Thank you for catching it!

Ah I see, I apologise. 

The sum is $1/\infty$, if I am not mistaken. If there were a capping to the value of $n$, then it would be a summable telescoping series, but this has no value of $n$, so assuming $n=\infty$, the sum is also $1/\infty$.

Yes, this is absolutely correct!

From here what we can do, since the area of a square is $s^2$, we can take $400/3 = s$ and just aquare it, and we get $16\color{red}{00}00/9$

This is a telescoping series. Why don't you try to do some research on them and then make an attempt. When you have done that, tell us what you got and show your steps. We will correct you if anything there is wrong.

Here is a lead: notice how the average of entire set is only $\frac {n+2}2~or~\frac n2+1$

I messed up and found my err. I have edited in the corrections. My apologies.

In red is what I have corrected.