Note: i^1 = i, i^2 = -1, i^3 = -i, and i^4 = 1.
Different powers of i still have the same properties. You can divide the power by 4 and determine the remainder to see if it equals i^1. i^2, i^3, or i^4.
As you can see, i - 1 -i + 1 cancel out each other, equalling 0. The last three terms of your sequence are i^97, i^98, and i^99, which are the same as i^1, i^2, and i^3. i - 1 -i = -1, so the answer is \(\boxed{-1}\).
Hope this helps, (CPhill will give a more vivid answer)
- PM