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What is \(\dbinom{n}{1}\) for any positive integer \(n.\)?

 Dec 15, 2018
 #1
avatar+100519 
+2

Just  n

 

We have n  things and we want to choose just 1

 

n ways to do that   !!!

 

 

cool cool cool

 Dec 15, 2018
 #2
avatar+701 
0

n choose 1 is always n. Similarly, n choose n and n choose 0 are always 1. 

 

 \({n}\choose{1}\) = n. \({n}\choose{n}\) = \({n}\choose{0}\) = 1.

 

- PM

PartialMathematician  Dec 15, 2018
 #3
avatar+701 
0

You can learn the binomial theorem and memorized pascal's triangle to help yourself.

 

- PM

PartialMathematician  Dec 15, 2018
 #4
avatar+647 
0

That's just \(n\) !

Imagine you have 10 cakes in front of you and you choose one. How many possibilities are there? 10 possibilities, of course! (Unless you are like me and you love cake so you sneak another one wink) This is for any number, not just 10, of course.

 

You are very welcome!

:P

 Dec 16, 2018

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