First find the sum of the numbers.
Also, since 0 has no value, I'll take it out for now.
The number series 1, 2, 3, 4, . . . . , 98, 99.
The first term a = 1
The common difference d = 1
Total number of terms n = 99
apply the input parameter values in the formula
Sum = n/2 x (a + Tn)
= 99/2 x (1 + 99)
= 9900/2
1 + 2 + 3 + 4 + . . . . + 98 + 99 = 4950
Therefore, 4950 is the sum of positive integers from 1 to 99.
Next find the average.
The amount of numbers = 100
4950/100 = 49.5
So your final answer is 49.5