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Arrange the following numbers in increasing order:

 

Latex version:

A=21/241/6B=12128dfrac22C=(181/5)2D=412181E=321/241/4dfrac22

 

In plain text:

A = (2^(1/2))/(4^(1/6))
B = 128^(1/12) 
C = (1/8^(1/5))^2
D = (4^-1/((2^-1)(8^-1)))^(1/2)
E = (2^(1/2)(4^(-1/4)))^(1/3)


I've gotten the answer C,E,A,D,B because C = 0.43527528164, E = 1, A = 1.5, D = 4, and B = 10 2/3, but it's incorrect. How do I solve this?

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Thanks for helping!

 Aug 12, 2020
edited by PocketThePenguin  Aug 12, 2020
 #1
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Here is the increasing order:
C = 0.43527528164,  E = 1,    A=1.122462048,    B=1.498307077,    D = 2

 Aug 12, 2020
 #2
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A=21/241/6B=12128dfrac22C=(181/5)2D=412181E=321/241/4dfrac22

 

A=21/241/6=20.50.˙3=21/6=22/12B=12128dfrac22=1227dfrac22=27/12etc

 

Change them all to powers of 2.

 

And stop accusing other people of cheating (on other threads)

It is irritating.

 Aug 13, 2020

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