qjin27

use the logic from previous answers to answer this, it shouldn't be that hard

\(x^2-11x+12=0 \\ (x-\frac{11}{2})^2=19.25 \\ (x-\frac{11}{2})^2-19.25 \\ b+c=\frac{11}{2}-19.25 \\ b+c=\boxed{-13.75} \\ \huge{🎉} \)

1. Make the quadratic

\(44=-6t^2+83t\)

2. solve the quadratic

\(13.2812 \approx \boxed{13.3}\)

I'm not sure that this is correct so can anyone double check?

Since the center is at (-5, 2), The equation of the circle is \((x+5)^2+(y-2)^2=r^2\)

Then you can multiply out \(x^2+10x+25+y^2-4y+4=r^2\)

\(x^2+y^2+10x-4y+29=r^2 \\ 2x^2+2y^2+20x-8y=2r^2-58 \\ 2r^2-58=80 \\ r^2-29=40 \\ r^2=69 \\ r=\sqrt{69} \)

(r has to be positive)

https://lingojam.com/TextToEmojiLetters

Its this, but you have to scroll down

wdym blocked

I think I used something else, but I forgot which website