we can use variables
a=# flowers Abul has
b=# flowers Bea has
c=# flowers Charley has
\(a=1.2b \\ 2c=a \\ \frac{1}{2}c=60 \\ c=120 \\ a=240 \\ b=200 \)
So the answer is \(\boxed{560}\)
I think its when y=0 so \(x^2=8 \\ x=2\sqrt2 \\\),
So the answer is \(\boxed{2\sqrt{2}}\)
I think because z=8 is the case that z is the largest, and z=1 is when z is at the smallest, so z has to be in between that
Did It come with a answer key?
I found online that you can do
\(720โฅz^3 \\ 1โค๐งโค8 \\ \),
Then you try out 8 cases
\(๐ฅ๐ฆ๐ง=720 \\ ๐ฅ๐ฆ+๐ฅ๐ง+๐ฆ๐ง=333 \),
Im not sure what to do from here, we could make \(๐ฅโฅ๐ฆโฅ๐ง\), but I don't see how that helps
I'm trying to figure out a smarter way to calcaulte the combinitions that don't involve casework, cause i'm too lazy to do it
The prime factorization of 300 is 2 ร 2 ร 3 ร 5 ร 5, so you try to find the number of combinations of 2 x 2 x 3 x 5 x 5
a what sided die
I think 3, 5, 7 works, so 15
