qjin27

I think its when y=0 so $x^2=8 \\ x=2\sqrt2 \\$, 

So the answer is $\boxed{2\sqrt{2}}$

I think because z=8 is the case that z is the largest, and z=1 is when z is at the smallest, so z has to be in between that

Did It come with a answer key?

$𝑥𝑦𝑧=720 \\ 𝑥𝑦+𝑥𝑧+𝑦𝑧=333$,

Im not sure what to do from here, we could make $𝑥≥𝑦≥𝑧$, but I don't see how that helps

I'm trying to figure out a smarter way to calcaulte the combinitions that don't involve casework, cause i'm too lazy to do it

The prime factorization of 300 is 2 × 2 × 3 × 5 × 5, so you try to find the number of combinations of 2 x 2 x 3 x 5 x 5 

a what sided die

I think 3, 5, 7 works, so 15