The quadratic x^2-3x+1-8x+11 can be written in the form (x+b)^2+c, where b and c are constants. What is b+c?
\(x^2-11x+12=0 \\ (x-\frac{11}{2})^2=19.25 \\ (x-\frac{11}{2})^2-19.25 \\ b+c=\frac{11}{2}-19.25 \\ b+c=\boxed{-13.75} \\ \huge{🎉} \)
